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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。4 A' r: b; O; U. R
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一般来说,2 x3 O: N2 J- M, I @* R# ?
. k2 B" M! u, O+ ?( p: H6 d二连赢的概率是25%
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: ]! ?# {+ S$ I) h/ Q三连赢的概率是12.5%# E% T) V; V$ \- \# J
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四连赢的概率是6.25%' g0 j+ y, U5 g. O# z( i
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十连赢的概率是0.09765625%- x7 |; `" A7 ^+ U" E+ H9 a1 g O
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这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。
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3 N+ R, g; o1 Q: a# i" F百家乐的真实概率含义是:9 t0 s9 G4 E4 p) o" m
9 e6 d- b& ?& t假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球1 u' W- _5 ^+ T6 W& W
# [" G3 m, X2 X; l; M1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。, f8 e% a+ R$ o: E4 v
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你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。5 f8 u3 Q/ c5 a- y8 z8 p
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你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。. G w' \0 _6 {6 s: K+ d, [& l
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另外一个说法是,& T" w- T3 P5 ?: ?: E# I) [
$ |4 o& b: K) {) `1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。& b2 E b- b) o8 E
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2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。
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再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。
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平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。7 R; L- M# [& V5 Z7 ~
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对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。
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) r9 v5 }8 s8 D6 D ?5 j举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。
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第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化% u7 T) x, F' u4 k2 r* f+ Y
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第三,凯利公式的问题在于:形而上学。
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1 @; b( B8 \5 g7 }1 Q3 L首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
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事实上,你玩的时候,基本上每次都能打到。9 |+ |& q7 s x% g
% }) B- g1 g* |" s* D因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。' K" Z. c% I) O- |8 d* @6 M
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