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[lastpost] => 2769001 【e世博】9月25日投注流水1951元 1758846613 22301
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所谓“缆”者,即一系列的投注,一连几铺的落注。最常见的就是当开了三铺庄之后,就开始买闲。第一铺输了,第二铺又再加倍;第二铺输了,第三铺亦继续加倍,到买中为止。6 J' b0 R% v6 l; i
6 K h# `( B1 F
有一次在赌场内遇到一位大豪客,当时他已输了很多钱,叹气说:“怎样才能赢钱呢?”旁边即有人说:“买缆就可赢钱。”那大豪客马上回应,如有不断的缆,他愿意出任何价钱购买。他是对的。世上没有不会断的缆,总有一次会断,一旦断了就要赔大本。既然如此,买缆岂能必胜呢?- P( N$ W! Z. \/ X
% C! x; ?6 S/ p4 f }要促成买缆必胜。首先我们要了解游戏规则。一般赌场都会设一个注码上下限的比例,最普通的就是1:150。例如最低是100元,最高,就是15000元,视个别赌场来定。在亚洲的赌场,很多是以全赌注总和计算;在美国等地方则以每一位赌客独立注码计算。目的都是一样,因为赌场要保障本身利益,如果不设上限,无止境地复式加倍又加倍投注,始终会给闲家买中,赌场就会不利。那么什么上下限都会介乎最少的1:100到最高的1:200呢?原因是开赌的人也计算过或然率,令闲家即使肯博,长期买缆,也要冒输大钱的险。下表就可以看出买缆的情况:7 X/ i7 y0 `6 L! [& C8 Y
& v- k' E& A8 D- N. @铺数 注码; c: ]3 F9 o, [ S) L" D$ d
- M( Y Z9 V; V- B
1 ¥1000
- T3 j5 t5 _% X$ ~. I2 H, i
" m) I" _0 e- _! y, _: l8 L5 Z7 A2 ¥2000' W# s- d( j1 j, f& A# I% o' g
: U! I3 ?( i7 P/ t7 e+ ~3 a
3 ¥4000
2 k8 X# u6 h7 p1 b+ O0 |8 u
" ]6 c3 e( ~( e% G+ T8 |/ m4 ¥8000+ g. i$ C: t3 q
3 A4 j3 l, |9 K! |; m+ N8 ^
5 ¥16000
/ Z& y* I. f# k6 }' ~1 x$ a8 b# m3 a# B' N9 q& E m) [+ s
6 ¥32000: {' w5 Y+ o6 t8 |$ b4 D" V& l
8 |4 h0 P x- a7 ¥64000
! a( c2 a! F. \% m T% U* V) w! p V4 I$ e. R# v8 B2 q2 n/ b% H* D( B
8 ¥1280008 j8 q: J+ l. R% X
4 V0 n2 V+ ]# F4 ~9 ¥256000
7 O& v! i# I: |5 k5 e
- B: u' f W* d( Q+ \可以看得出最尽只能买到第八铺,第九铺已超额。如是者,必须于八铺之内买中,否则就要断缆,一次断缆,所输的钱,要连续赌四盒牌不断缆才可赢回损失。
0 l- C* r, o% h, c
# o4 ^5 [7 b6 M) g经统计及电脑分析,要达至长期不会断的缆,至少要十铺为标准才可保障长胜,但十铺又刚好超过了注码,所以是有矛盾,不可行。任何一条公式缆,无论庄闲的次序是如何排列,9铺之内还是有机会断,十铺以外则机会较微,愈长则愈难断,这纯然是溷合或然率道理所在。0 U; g; @( }0 G4 V% Y; s* ~' S
! C1 L* G+ r" G& N5 x' f" J/ d换言之,没有永不断的缆,即是代表有必断的缆。非常正确,想缆不断可能很困难,但想其经常断就不成问题。特别是四铺或五铺的缆,差不多每一盒牌都会断的。因此我们就可运用这个逻辑,或然的东西难赌,必然的东西自然是易赌,下注的方法就是:
( ~1 x9 F" T5 }4 g) \* d$ @. j0 ~3 m6 A
举一个简单的方法:
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B B B B B; O" B/ C/ t3 e W. G
6 {+ F6 p9 n$ [5 _( c% _庄 庄 庄 庄 庄
* Y) Q6 c# ~( G, f
' D2 r8 E4 |9 S6 _: c% B正常的买缆会是:输了第一口买庄¥1000,第二口买¥2000,输了第三口买¥4000,输了第四口买¥8000,直输四铺后,第五口买¥16000。这么一旦连开五铺闲,就马上断缆,一输就是¥31000元,亦即要赢回31铺才可打和。这个方法基本上可以断定,长赌必输。因为出现连续五铺闲的情形多的是,一盒牌内断三次都不出奇。6 {+ Y! e# q" z# J3 l
7 T0 a$ M" D; r8 j( k3 G/ W ]
要赢就要做刚刚相反的动作。每铺都是买闲,如果开庄,输了又继续买闲,反正每次输都只会是输掉一个起步注码。如果开闲的话就不同了,第一铺开闲买中¥1000元,第二铺就买¥2000元,再中第三铺就买¥4000元,中第四铺就买¥8000元,到第五铺就买¥16000元,全部连中五铺闲的话就赢¥31000元,一盒牌内能中一条缆就不会输钱,中超过一条肯定赢大钱。
- G \9 \; _7 u% `* G
6 V$ i$ Z" Q/ c/ Y6 ^: C经本人统计,平均断得最多的当然是四式缆(四铺连续),大概每盒牌有二到三次。五式缆则平均每盒一到二次,六式缆则每两盒就有一次。七式及以上就不会是每盒会出现。所以我认为五式缆会是比较可行,既是常见,也可保持不俗的利润。5 {1 F5 A/ u, i+ o7 e9 q
! a* j5 i( a1 y6 l/ q2 W) B, A' a) n
赌这种反缆的方式,是需要相当耐性,必须要坚持信念,相信这种现象一定会出现。输了前段的不可气馁,一次遇五闲就可连本带利赢回来。另外,有的时候在一盒牌的前段己经出现连续五次遇了闲的现象,那利润己到手,已经可以再等第二盒。
% F# g( \2 C9 n( r! o* j
- n- o) A7 _) a( L' W2 r1 L问题是如果长期只赌一方,庄或闲,那会令其他人觉得很奇怪,所以我提议一条公式如下:
: k7 z5 h& e) m+ T* Y
, }, ~/ n5 g4 V! `& O' n) Q7 X5 uB P P B P3 n U" g+ R2 L- r& ]; `
- C/ l6 S" P* q! ` }2 p
庄 闲 闲 庄 闲
* i8 p% \8 d B0 z. K4 G- M8 ~' m) E; I% b4 e% {1 {# E
依以上的次序,按序投注,赢了第一铺庄就买闲;赢了第二铺闲就买第三铺闲;之后再买庄,到第五铺又买闲,全部中齐就重新由头开始过。不要担心,这个排列次序,差不多每盒牌都有出现。4 m, |- N3 b+ F H3 L4 D
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