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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。
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一般来说,: _+ ?" X/ Y, R0 ~$ w8 [
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二连赢的概率是25%
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# [) e6 `2 l4 s9 S- z; Z三连赢的概率是12.5%- {2 p! E ]! k3 h
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四连赢的概率是6.25%
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……
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4 r. r; y0 U" L1 f十连赢的概率是0.09765625%9 J3 W: h3 L+ v. V
# z* a. x3 v: ~3 r, U$ Y: ?. C' o这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。
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: @+ J8 o4 o. z! Q+ v百家乐的真实概率含义是:9 e w$ z4 g+ _& ^% g$ `6 N
$ Z& V0 j3 d: k$ A假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球+ \, a t: {0 E4 _, p# H/ [
9 z5 y" v# i# Q" b2 `. q. A1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。- ~* u/ {0 F( ^. m- a6 Z- h* i }
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你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。" Q- b9 d* F) c' Z, ^
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你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。
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另外一个说法是," f7 n, z) V+ [: ?# N( i* ^
6 H* h4 S- @, y1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。
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0 G; x# B2 f* i2 E2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。' V) r7 U9 a7 w% h z$ S
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再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。
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6 J' o, E u& {0 p; j$ Z. u7 G& p平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。
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对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。1 \% Y# x8 i- j& w
$ X- [2 r7 a+ O4 U' P. h举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。* z" B7 o+ t2 P' N7 r, C
& [$ t3 \4 P& R" z第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化
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第三,凯利公式的问题在于:形而上学。
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首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
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5 x7 r9 I8 l. d4 z% ?( L事实上,你玩的时候,基本上每次都能打到。 @6 [" W! Z/ o
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因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。
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