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[打法交流] 百家乐投注法的一个矛盾(转)
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1#
很多DB专家认同的一个方法是赢冲输缩,就是中了这一注下一注就要加大注码,用赌场的钱去博赌场更大的钱。  前段时间看到一个纯数学分析法 与这个相反。
$ d3 _4 ~9 H: H* G& \: e. b0 f4 u/ {  数学法是这样的。保证在你中和不中的注数相同的情况下必胜。
$ z& ^3 Z0 z  C# i9 d7 Z" U比如 买了4次 中了两次 错了两次。用+代表中 - 代表不中,那么共有6个排列    i% ]% b2 I, x
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1.+  + - -& p4 B3 G: o# B* Y
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2.+ -+ —
$ p) U6 [7 ]2 `8 `5 Q3.+ —— +
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  |1 \7 V3 D+ H4 Z( M9 U4.- + -+0 @0 _; I/ o7 w: i
5 - - ++
& @0 Q7 I: a3 t8 \6- ++ -
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2 m0 P; `, o0 B) ]数学叫做增值法 就是赢了就减注 输了就加注 (合理加注 不是翻倍 翻倍可能承受不了)  a8 m" V0 n: `+ d- ]  p0 e' a

3 s" B8 t9 S: h" O: }: q8 f2 c打个比方刚开始是10块一注   赢了下一注减1 输了下一注加1,那么 第一种排列方法 输赢是这样的 + 10 +9 -9 -10 不输不赢 第二种排列 +10 -9 +10 -9 赢了2块  第三种是+10 -9 -10 +11 也赢了两码6 `' J* h% O3 A1 {5 F3 ]/ V# J" I
第四种排列  -10 +11 -10 +11 赢了两块  第五种排列 -10 -11 +12 +11 赢了两块  第六种排列是 -10 + 11 +10 -9 也赢了两块  除了第一种排列不输不赢 后面都赢了两块 。所以可以看出来 在猜对猜错次数相同情况下 输冲赢缩是合理的 而且能保证小盈利。   因为和很多会赌的人认同的 “赢冲输缩”相悖。如果能控制住自己的注码,个人更偏向于数学方法 。大家觉得呢。 输冲的冲不能类似于用揽 否则后果很严重。如果有1000本金,基本码是80,输了加10 赢了减10  即使连续几把不中也是可以承受的,到最后猜中的和猜错的一样 就能赢利,当然如果猜错的多 ,传统的“赢冲输缩”也是不能保证盈利的,除非刚好冲得时候 赢了 万一是冲得时候输了  一定死的更惨。8 H* f, E4 x( K6 P4 ?

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41#
其实任何时候都感觉挺矛盾的
avatar
看上去第一个的确是一个矛盾
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39#
矛盾的确是特别的多的啊.
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38#
有矛盾?就是下注了,赢不赢看运气
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玩这个是要理性一点的了
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确实是很矛盾了,这个不好说的啦啊!
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35#
其实如果我们解决了自己的矛盾就好了
avatar
矛盾是矛盾的啊,看的懂嘛
avatar
这个投注法也是要看看的了
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32#
方法也是值得去学习起来啊。
avatar
无论怎么投感觉都是矛盾的
avatar
楼主这是要冲上天的节奏啊,都已经盈利了
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29#
这一次方法在这里的运气还是值得肯定的.
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这样的盈利成绩也太牛逼了吧,都让我万分嫉妒了
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27#
此次的投注结果也是失败了啊,还是有点遗憾了
avatar
26#
并非所有人都可以盈利的,所以楼主你很厉害
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