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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
. s: x4 P, s: D( x2 s; |$ ~1 s1 l: X0 X# V2 D# b% R3 @2 ]
假设大路开这样的路:/ G U: O' f; h6 y1 `# N
1 ~$ f, x4 \( r; P7 u @9 w1 F B 12121212121212121212121212121212。2 h" ~6 X s) @, k/ a& C/ u# n
' r' ?2 l: O% t6 T2 n 按2珠路,就是BPBPBPBPBP。
$ P% E! y9 E8 G" X9 U) A' Y" n( w/ J1 [7 |
如果我们去掉第一口,就会出现完全相反的结果:
; n2 ]" n" y7 y0 O4 _
: K/ ] X% S8 H; S/ [ 21212121212121212121212121212121。5 `4 o, N5 J( z" f
7 A% `4 b( Z# k# L1 q# X p2 S- g9 s# V) o
变成了PBPBPBPBPB。! k2 s/ ~! g+ D1 G, B
) D( {+ n9 w C- y( J7 i 如果我们再去掉一口,又返回第一种情况了。
% N* j- |/ ~: ^6 w; Z9 d
) _4 Y2 T! ]" A: ?4 s6 Q 所以每一条大路,按2珠路排列,有2种不同的路数。
6 S2 k8 r' ` n# C6 Z* w7 B9 S! H. E* Y8 t+ a' x* q5 E
再举一个列子:0 q& I7 D/ V4 ~9 r: [: N, P. E4 S
/ C" k! |) G4 f 大路:122122122122122122。
d' ]* Z. s, w+ a( p3 F1 u8 d8 U8 X U9 d
按三珠路排列:
- N* d' N+ Z/ C0 e
- q& h2 c7 k- h2 X; A' H# K4 [, | 122,122,122,122,122,122。
7 U7 u% c1 S) x4 O, J% P
( k, X) Z' U0 y6 W9 e 去掉第一口,变成: Q2 o) Z/ w! a. v
- h) k5 v0 M2 H: W' l 221,221,221,221,221,去掉前2口,变成:
" \* v! X" N% d) Y
& n5 y1 {- E3 ?' T7 o4 i k 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。; p: T0 x7 I% v" d" E) m! q, K
$ K+ X! X* T U" }
同理:按N珠路排列,有N种不同的路数。
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我提出这个的意义在于:2 w% E3 B/ S( v) h ~: N- P
! T0 E- ~9 Q1 j9 G2 ^ 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。# }- n% s9 r r R6 T6 [
v2 P& n: [9 o 2、为三多理论提供了下注的多面性奠定基础。$ j( }1 U" F8 B- |; e' E
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。7 |5 A: Y7 ^7 L2 N
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