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[lastpost] => 2753621 【星宝】8月1日投注流水73502元 1754060318 小希哥
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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
0 C+ T+ D: U6 g; F Q0 S' ^. ?. R0 l7 ?7 d& P+ Q
假设大路开这样的路:! u' o5 i# ?. l. K h9 @
1 T% a8 Y6 m* S
12121212121212121212121212121212。' L; e5 ]% K5 P7 @4 V; F
|5 \+ c! ~4 `8 q. _! t4 j. i 按2珠路,就是BPBPBPBPBP。7 Z9 ?( ]% X% w8 O5 Z6 z" b
7 E9 o5 T# n" a* r. _ 如果我们去掉第一口,就会出现完全相反的结果:
, q0 B0 a$ v$ C0 P( [' p% I: a$ U+ @2 l9 J; H# m" {4 [5 Z3 C
21212121212121212121212121212121。
+ G4 l8 c7 N' ^* m' K0 y/ p
% ]& ?* j( A1 N7 v 变成了PBPBPBPBPB。
# a: c9 U' F* M
* A& L' J6 D, D2 D& K/ G. c 如果我们再去掉一口,又返回第一种情况了。* o! p5 _# E) w; y- O
" K+ p& o3 y1 |; \/ e 所以每一条大路,按2珠路排列,有2种不同的路数。
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/ U/ s+ p, c0 C% z, l. g 再举一个列子:
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/ F7 k+ L' t2 a/ o0 N 大路:122122122122122122。
8 e- h" l# Z7 K% k E0 ]
9 t, Y! R' s/ g& j% e# D- a! l) D# u 按三珠路排列:4 u3 N! t/ r U9 O0 ]" N0 ^
+ [! q/ c5 h$ D" O* |, X 122,122,122,122,122,122。1 U% E- u; ]+ k! T
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去掉第一口,变成:9 q9 v5 }/ o5 O
) Q8 @8 z+ j3 j9 N
221,221,221,221,221,去掉前2口,变成:
4 ~( l; O9 S, N- {5 y" T: F) B# }; U' n5 ^2 T+ N- M
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
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同理:按N珠路排列,有N种不同的路数。
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+ l9 h/ Y e! }3 [* X4 Y* H) j H 我提出这个的意义在于:+ |! d! p5 m4 `/ |5 |
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1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。5 o- }: ~, K( `
4 z4 B9 F( n) j# ] 2、为三多理论提供了下注的多面性奠定基础。
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。& N3 d1 A9 b9 l9 i# A& t& t
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