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1 D# S) b$ n/ [5 |+ i1 A
- ~6 m. Y7 ]; r通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。4 u6 u; ?6 _, ]1 L# ]! p
4 A* S7 k" N3 \
假设大路开这样的路:
3 l. F j/ x! f* W8 E* f3 [1 |% q* @, T! ]2 R V
12121212121212121212121212121212。
! T- M0 c) y U8 ]2 _$ w# ^4 }. [' g6 C; s+ A
按2珠路,就是BPBPBPBPBP。4 ?/ u) q& f6 e3 G
8 o: ^) @) b- I- n; i9 ?: W0 }% D* s 如果我们去掉第一口,就会出现完全相反的结果:6 L6 M5 `- f. @) E7 ^" k
- A6 M- n8 q( ^
21212121212121212121212121212121。0 D8 v" E. [: ~# R. ]- [
7 i/ n" h, J4 E3 L3 }
变成了PBPBPBPBPB。
7 |4 C; H& U, A8 R- r
X7 ?/ ]. R- t8 [6 v) c 如果我们再去掉一口,又返回第一种情况了。
- o; e- p3 @! _. r; T' ?. R
! O% Z2 P C3 Z5 v 所以每一条大路,按2珠路排列,有2种不同的路数。
3 F" ~# F/ x' ?1 X2 o+ z, l4 m, ^- k% u7 L$ q( x
再举一个列子:
. N, i+ W' f; B2 f9 Q* Q) n0 E- u- T% V7 {* [0 s
大路:122122122122122122。 e* C7 N3 G3 n' u: w; r$ e' D- c
6 k1 L. Y m$ j3 t9 n5 G# r O! N 按三珠路排列:
l4 z7 ^) n4 U4 G, G2 H$ C# T% D% o; H, x' V& o5 c: F
122,122,122,122,122,122。
2 h' u2 h. W- O0 g1 g2 n, O; s( D7 R
去掉第一口,变成:0 H: V* C# A. G7 K, @* m( F9 R
/ H/ c# B) \! o5 j' m: V+ A 221,221,221,221,221,去掉前2口,变成:
& w7 j/ a, j$ q: ?$ ^. ~7 w. I7 U; i1 L2 A7 C/ _* U8 O
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。3 x- i) ?8 Q* K6 [, v
+ k' ]* G. w9 p% D: t: k6 G
同理:按N珠路排列,有N种不同的路数。
, K4 N. t8 l" e
% `1 z. H8 P: X 我提出这个的意义在于:- c( V9 T6 W! A7 D* L+ S9 s/ Z3 _
3 B' Y4 n+ q6 N" \0 S! I- M; W3 e( y
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
9 X4 I# Z' G( D. T- v
5 z) e( t [- u0 X% Q7 q! m- n 2、为三多理论提供了下注的多面性奠定基础。, |" `, a: ~0 j; g# C$ Q
+ r% M9 {% x- F; H1 k$ A
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。: u# q* `! L6 t( x1 E* O
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7 a4 Y2 Z7 K7 `3 K( @' n+ x
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