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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O1 F3 K# D* u7 @% {, l; o* ~7 `
}1 g; s p( n
发现了一个有趣的现象，
2 G9 P2 u( T' |9 v每一条大路，( k! P5 d) W H: S% M
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f8 Y6 o: t8 M" p! ]2 l6 p
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z" A! M) Z# J- M B7 S8 u% |
按4珠路排列，有4种不同的路数
; C: m, L1 \5 f. Q按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
5 C; I. F0 _! S }; [% \" y; E ]什么意思呢，可能大家一时不清楚，' o9 Y0 J9 W3 `
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
) B+ D: I$ X8 y; P- H假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
6 B# u1 k$ d, D5 K+ {12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h' {9 q/ ^* z1 y( e0 Q. K
够极端了吧0 K8 _% Z' _3 X7 ]# Y, z
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F% P) h+ r9 {( l+ O" s2 `8 [- `
如果我们去掉第一口，就会出现完全相反的结果：
" x1 B7 t# ~& Y9 x4 b21212121212121212121212121212121
, S) T9 K" [) C* x7 H4 D1 O. R变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
- Y, `1 T. s# ^' S& c如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
$ E, k3 i% o: A) B所以每一条大路，! R6 V# q$ h. c; z% O
4 i! m' A2 a$ q$ ~2 c+ W! F按2珠路排列，有2种不同的路数。) K+ Y5 p* [! p( ?4 ?
再举一个列子：
7 p5 Q; H( s3 p2 S' P+ k大路：122122122122122122。。。
6 P2 f* r7 ~$ _0 i: u; w4 Z按三珠路排列：
( R! u8 B2 F( ^122，122，122，122，122，122。。。3 L; w, p7 J3 A% }6 k2 ]! m
去掉第一口，变成：6 G2 V! \" L' c" k: d
1 m) y. P/ o7 T! @$ f+ g8 [* p221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M" ]% N% i- e' @0 w! N1 z+ I
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W* X" e F+ C* f9 K F
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
4 x* C0 ?# v4 C' \& Q/ P) S去掉3口，又返回122，122，122，了! ^, e* |" E. b, ^/ y. O' h
所以每一条大路，' L: h2 ]9 Y* [& Z2 ~8 `
按3珠路排列，有3种不同的路数。
0 E4 M2 h, j- i9 U' P9 k) o* u同理：按N珠路排列，有N种不同的路数。' c# I% G0 W- V: e6 D5 l) x
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O4 l: ` X( ], L5 g2 B* _
字串83 L: R) G1 V- s2 Y+ Y
& o3 T+ P$ w' @% A2 U3 I- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
1 d8 W! G& X& i# i1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
) P% D L: x. F' j0 G- G2、为三多理论提供了下注的多面性奠定基础。& {+ z' j, j8 e$ U0 A
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.4 v( n2 {; W: b4 n& }. l
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