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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O; ~# T0 d% r% |$ N2 H" Z( P2 w
, q2 J6 T4 m. j% L+ F发现了一个有趣的现象，
1 M/ l) j h5 o9 d# s6 X5 b! u- H每一条大路，
( ]4 E. b8 [/ e* k按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f) K3 C1 v6 N" }# J, Z9 ?0 \
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z2 H) K1 G3 B. ^7 s
按4珠路排列，有4种不同的路数1 s( p. @8 s. R! A
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C4 V' ^! R7 K) ~" O' k6 S) b
什么意思呢，可能大家一时不清楚，
# M4 S& \. d6 h8 v3 {) x# G: N7 ]! S我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l [* ?4 l* I& R
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
& B( S+ l- c- J: S; m4 S12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h1 A0 A o2 A f1 d- M, ?
够极端了吧
; x! ~; M2 [2 i4 L7 ^& U按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F" Y5 B( \9 A$ c0 R
如果我们去掉第一口，就会出现完全相反的结果：1 U5 Q A2 K. l; R. Q
21212121212121212121212121212121 q, l- d* x- S3 k3 W5 j2 \! h
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C5 D# r+ v9 b9 w' Q2 y. u
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
# B2 v4 T$ u U1 x所以每一条大路，! R6 V# q$ h. c; z% O
9 P6 j9 ^1 j' U按2珠路排列，有2种不同的路数。 ]% H( i- U, n* A
再举一个列子：
5 `, M' k2 o- o" U大路：122122122122122122。。。- S* k b# [# h8 ]
按三珠路排列：
u5 e- }5 c+ s7 `8 w122，122，122，122，122，122。。。' O& A; p: c4 M# `- t9 K4 o0 T
去掉第一口，变成：6 G2 V! \" L' c" k: d
0 i; t6 q/ n6 G6 Q5 S221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M6 ?9 n5 i& h, n8 ^! a
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
; w3 u; c y s# a& x- @1 {. p212，212，212，212，212，: y& l, B; I6 e- m. J# c) `, ?. s4 J6 m2 F& z0 g
去掉3口，又返回122，122，122，了7 D/ s& W5 V- F) O7 T0 d% k; I8 i( [
所以每一条大路，
" d( k6 ]" }: }" g0 A6 L- L按3珠路排列，有3种不同的路数。( M* e! N* I0 W# ^! C9 L0 o% E0 p
同理：按N珠路排列，有N种不同的路数。
% b+ Q0 O! [/ J, d- o我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
$ e: }2 u1 `: i4 k; C" N$ K字串83 L: R) G1 V- s2 Y+ Y
: s w5 n6 U9 S" l& G- p, d3 [6 U. s5 J' [0 {1 A" m' k( @3 l/ T' |2 v9 K, g( ~* y
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
) L$ i; o$ D0 F5 @2、为三多理论提供了下注的多面性奠定基础。
4 M# ^7 d$ k! T% g$ q3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.; ^5 F( Z6 Q( `% N0 i# P' l
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