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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
2 p+ T: p# Q7 Q8 q# `9 N' [( `2 b- _9 p' ]) }: c" r6 g7 p4 Y
发现了一个有趣的现象，' o" E4 b! `! l. o8 c3 d
每一条大路，0 F5 g- u" c/ U) C( ]& K* D8 q* l
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
5 F. m: ]: e6 x8 p/ O, x8 I* W3 O& d按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z! \" B. [/ I& S5 {- G4 M4 @+ w' h
按4珠路排列，有4种不同的路数' _, g4 L) h2 w& W) b
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
! U$ t. S* R9 h) `什么意思呢，可能大家一时不清楚，) |& W8 @9 U4 I& g
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l. t1 P7 V* L/ B W3 j5 j
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u; W$ z$ U8 ~+ K/ P
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
, ^/ D% b4 T0 t A6 l- a; }7 q够极端了吧- {* s+ M- @+ ?. X3 o( @
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F! M' w. c' S6 {: o9 N5 H0 E7 j
如果我们去掉第一口，就会出现完全相反的结果：
. v6 H% _/ a: v; e- d' T212121212121212121212121212121210 Z4 U# [# L7 E6 N+ b
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C2 b5 c( Z* \1 F& r9 X
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O/ p6 y( c' B. @% Z6 r {- @
所以每一条大路，! R6 V# q$ h. c; z% O
2 Z2 }" X) G; d9 b+ y9 u按2珠路排列，有2种不同的路数。# U9 ~1 z! s7 N) n
再举一个列子：. Q# Q. n; I0 h2 G/ K" ?" E
大路：122122122122122122。。。
* r& `- F$ _: h3 a按三珠路排列：4 V! P% H6 U- s
122，122，122，122，122，122。。。) H, ?* V Q0 H& u4 b
去掉第一口，变成：6 G2 V! \" L' c" k: d7 L/ e0 b, o N3 l, K1 s( Y
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M/ f$ I) q* @/ S8 V" @- j
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W. b9 r/ p: o$ E. r& r5 p' M
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `% r6 P% v/ W% _ y+ ^3 E& b: h
去掉3口，又返回122，122，122，了
+ T7 P: y( v5 F所以每一条大路，/ U! \; l/ L( X" h
按3珠路排列，有3种不同的路数。
' k% i5 l% N1 [3 ~同理：按N珠路排列，有N种不同的路数。
' L" N' R) O( m* p6 l/ ^! Z$ j我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
2 t6 p; C; S0 F: ?2 U5 B字串83 L: R) G1 V- s2 Y+ Y s: C" L, `2 i* S l
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
' b+ R4 G9 H- |! `6 l0 Q1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |9 L! A, E/ W) Z/ a7 e7 t
2、为三多理论提供了下注的多面性奠定基础。- `$ B1 T3 N5 n, ~& B6 ~
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
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