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通过我几个月来对珠路理论的研究,5 R+ y* d$ ? k6 I7 G/ O
6 j$ ?& I! O; ^5 Y; _. Y# |, m/ t( O# \
发现了一个有趣的现象,
) i1 V1 y6 B3 M* W; { s每一条大路,4 g+ N$ e; j6 m, ~ {: f0 ~; b# b
按2珠路排列,有2种不同的路数1 _% l2 j Y8 @" u) {# f5 z- q4 F+ n5 a( g s
按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z) v/ N/ B- f% s T
按4珠路排列,有4种不同的路数
! t1 d1 \7 s+ K! e( \: J% ` B4 D' d按N珠路排列,有N种不同的路数。: n1 f3 R9 @ p% ]* C
. ?5 O4 R1 @3 H0 G% I% w什么意思呢,可能大家一时不清楚,
7 Z6 h# |6 F" _我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l
0 H! t9 T$ S2 X6 g6 e/ J, a假设大路开这样的路:! z ~0 G3 v. K' o5 A4 ]" }5 w# u2 q# {3 ^6 Y7 n* D( i' d& i* H. R) v1 u
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
) j( [) H1 R( S, k5 K够极端了吧5 B- w) W R/ m* s) N: a
按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F1 u% t. Z; H( \- ?* P2 ]
如果我们去掉第一口,就会出现完全相反的结果:8 ^4 s2 Y% W- s6 d
21212121212121212121212121212121
, X. ^8 t: T. w+ b7 i, u变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C8 H) e% q; B9 b6 `& G! s$ q- T9 g
如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
5 d& A, ?* {& {% d( E& s! \; d7 u所以每一条大路,! R6 V# q$ h. c; z% O& c4 Q( N6 P. }( {1 M+ J
按2珠路排列,有2种不同的路数。
8 {2 E; ^1 g& |再举一个列子:
" o+ L+ W5 k: l( Q8 ~2 |大路:122122122122122122。。。
# ~3 |; [+ c( b5 }按三珠路排列:& o4 D g; H5 x0 @" r% E
122,122,122,122,122,122。。。; I1 o. \7 [0 r" i" _
去掉第一口,变成:6 G2 V! \" L' c" k: d
% f0 E! t0 Y i9 t7 J221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M# I3 g% \5 t3 c5 M. V, l0 \
去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W
+ K) r* z# ^# S, @ s) R3 u I% H% K" W2 q212,212,212,212,212,: y& l, B; I6 e- m. J# c) `; A. k5 \( X8 g4 d6 {. O h3 J
去掉3口,又返回122,122,122,了
9 v* _! H7 M$ `/ Y8 J+ x4 L% s所以每一条大路,$ g# q* }5 m: z, e+ R& B
按3珠路排列,有3种不同的路数。
5 H- y7 d7 z: w& o W' ?/ P同理:按N珠路排列,有N种不同的路数。
( C( h& I6 X; H: L- Y我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O
) D2 R i3 Q0 ~5 X% ~字串83 L: R) G1 V- s2 Y+ Y
V7 F0 H2 A# j& n$ |- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
0 }) y4 v% H% e" y. _ y1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |8 H0 h- a& T5 `
2、为三多理论提供了下注的多面性奠定基础。
Q+ A0 d8 V |8 Q3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.$ X& e- u# F; a/ S: `) H
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