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[打法交流]
分享3d杀尾秘籍 助您轻松预测和值（四）（转）
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分享3d杀尾秘籍 助您轻松预测和值（四）; u/ S0 s3 _& p7 \4 U( M9 M
(十八)同尾反杀排除和尾
E L6 `) l$ D选和值尾，我们找它上一期跟它相同尾的下一期是什么，那么我们就可以排除什么。同尾反杀这个概率还是很高的，它具体就是说，我们从下往上找，不管隔多远，只要找离它最近的相同的尾，找着相同的以后，相同的尾下面那期开的是什么尾的和值点，通常下一期我们都是可以排除的。这个方法的概率很高，同样，我们可以把这个方法也用在就是百、十、个位分位的杀号上。/ ]' F' l7 I5 v0 T% z. o
(十九)用大号排除和尾2 p, U% A: j3 _ `7 w+ b" O O
最大数指的就是指在0到9十个自然数当中，最大的数是9，我们用9减去上一期奖号的和值尾，那么得出的数就是下一期我们可以排除的和值尾。" ]! K; u0 O& _) |- @4 h( k
(二十)跨度排除和尾! e2 s4 h0 x- a3 A+ u) u: X
这个方法是这样的，例如某期奖号是924，那么它的跨度是7，也就是说下一期可以排除尾7的和值。尾7的和值包括包括7、17以及27，也就是说这三个点位所包含的全部的开奖号码，我们都是可以排除的。7 ~, ?2 c0 a; U1 u# d+ ^
(二十一)平方和排除和尾' I! A0 z m/ |3 x
我们把奖号的百位跟百位相乘，得到一个数，十位和十位相乘又可以得到一个数，个位和个位相乘也同样的可以得到一个数，我们把百位的数字平方运算，和十位平方以及个位平方，把这三个数相加起来，我们取它的尾，这个尾的数就是下一期可以排除的和值尾。
! N' g" f: P, p, G( w) j（二十二）三期和尾差排除和尾
" S ?; r+ T, h" g* ^- j所谓三期和值尾的差，就是我们用两期的和值把它相加起来的和，减去第三期和值得出来的这个差，就是下一期和尾不出的和尾（大减小）。+ D6 d% q6 f3 U5 K/ j( [
(二十三)奖号百位排除和尾
3 \ H1 c @% Z用上期奖号的百位排除下期和值尾的方法，而这个和值尾，它通常代表是两个或三个的和值。例如，某期奖号开出的是924，那么百位的号是9，也就是说下期应该没有9的尾的和值。
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